I know this place from Phaeohelotium succineoguttulatum.

Yes, this Orbilia fits well the other samples of this species from Spain, in my opinion.

Can you tell me the date and collector, also the herbarium number? If you wish you can send me the plates by mail. It is funny that this species is so far found in Spain on Australian substrate only. In Australia we had it on Acacia, Jacksonia and Eucalyptus.

Was it a log or branch? On the moist ground or exposed? Detached bark?

Thanks!
Zotto

Hi Zotto

The ascomata were found by me on dettached pieces of bark lying on the ground in a relative moist place. The date was february 28 and the material is keeped in my herbarium under ERD-6658. I'll send you my pics.

This fungus grew together with another still not studied orange species. Among the ascomata there were tri-arms conidia that perhaps belong to any of the two fungi... 

Thanks a lot

Interesting! Australian O. albidorosea has no tri-armed conidia but Dwayaangam (4 arms, 2 pointing downwards)., so either Spanish samples are a different species or the Trinacrium belongs elsewhere. Can you show me photos of the conidia?

Please keep me informed about the orange fungus.

Hi Zotto

As I said you yesterday, among the ascomata of albidorosea grew few others of an orange Orbilia not well preserved that I could no to study. No free ascospores I have seen. Only a few ovoid ones inside the asci. Their paraphyses are inflated and with a gel cap. But nonetheless I feel you can to identify this other Orbilia.

The showed three-arms conidia are somewhat under this other orange Orbilia rather than  albidorosea.

This Trinacrium is very probably the anamorph of Hyalorbilia erythrostigma which uses to parasitize on Orbilia spp.

The orange Orbilia is not easy. The spores look mature because their SB is very long and uncinate, and theiy measure 5-6 x 2.3-2.5 from the scale. This is a bit too narrow for O. gambelii but I have hardly another suggestion. Goog would be to see whether SCBs are in the excipular cells, and to see some paraphyses.

I'll try it, but ii will be not easy

Thanks!